What is the output frequency of a 4-pole rotor turning at 1800 rpm?

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Multiple Choice

What is the output frequency of a 4-pole rotor turning at 1800 rpm?

Explanation:
The frequency output depends on how fast the rotor turns and how many magnetic poles the machine has. The relationship is f = (P × N) / 120, where f is frequency in hertz, P is the number of poles, and N is the mechanical speed in rpm. For a four-pole machine at 1800 rpm, f = (4 × 1800) / 120 = 60 Hz. So a four-pole rotor spinning at 1800 rpm produces a 60 Hz output. If the pole count were different, the same speed would yield a different frequency.

The frequency output depends on how fast the rotor turns and how many magnetic poles the machine has. The relationship is f = (P × N) / 120, where f is frequency in hertz, P is the number of poles, and N is the mechanical speed in rpm. For a four-pole machine at 1800 rpm, f = (4 × 1800) / 120 = 60 Hz. So a four-pole rotor spinning at 1800 rpm produces a 60 Hz output. If the pole count were different, the same speed would yield a different frequency.

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